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I have built an application that will play six hours of mixed media for an old peoples home. Included are videos; music with moving images backgrounds; and quiet times with no sound.

The script for this is based upon some 20 playlists, example entries are:

xbmc.executebuiltin("PlayMedia(/home/pi/.xbmc/userdata/playlists/video/Sect2_vid1.m3u)")
time.sleep(437)
xbmc.executebuiltin("PlayMedia(/home/pi/.xbmc/userdata/playlists/music/Sect2_mus1.m3u)")
xbmc.executebuiltin("SlideShow(/media/TRANS_SD_B/Interlude,recursive,random)")
time.sleep(353)

To start the script I have a line in Home.xml

<onclick>XBMC.RunScript(special://skin/scripts/leonie_script.py)</onclick>

The difficulty is that there seems no easy way of stopping the script short of turning off the Raspberry Pi. Even if I turn off a video that is running, when the next xbmc.executebuiltin comes up, the next item starts running. The script is still running in the background.

I have mapped the '0' button on my remote to 'StopScript', thinking I could have a 'while not StopScript' statement at the top of my leonie_script.py. This is aimed at putting leonie_script.py in a loop waiting for something to happen, while playing the content.

I would very much appreciate assistance with suitable python code to stop the complex leonie_script.py script. I can't find anything after several hours of looking. The skin is Confluence.

A quick hack/fix would be for your "StopScript" to create a control file (eg. /tmp/stop.file) which you test the existence of before every step in your leonie_script.py - if the file exists, you exit. Eg:

Code:
def checkabort():

  if os.path.exists("/tmp/stop.file"):

    os.remove("/tmp/stop.file")

    sys.exit(0)

def checksleep(timeout):

  while timeout >= 0:

    checkabort()

    timeout = timeout - 1

    time.sleep(1.0)

xbmc.executebuiltin("PlayMedia(/home/pi/.xbmc/userdata/playlists/video/Sect2_vid1.m3u)")

checksleep(437)

xbmc.executebuiltin("PlayMedia(/home/pi/.xbmc/userdata/playlists/music/Sect2_mus1.m3u)")

checkabort()

xbmc.executebuiltin("SlideShow(/media/TRANS_SD_B/Interlude,recursive,random)")

checksleep(353)  # Is this one needed?

In your 'StopScript', simply create the file /tmp/stop.file, then stop the current player.

I'm guessing that the various xbmc.executebuiltin() calls will block until they finish, in which case execution of the leonie_script.py only continues once the player is stopped, and the script should then exit if/when it detects the presence of the "stop.file". If the "StopScript" is executed while leonie_script.py is sleeping, leonie_script.py will exit as soon as it wakes up from sleep. You could of course implement a sleep that wakes every 1 second and checks for the abort, I've added that above too, so now leonie_script.py should execute more or less immediately after the StopScript is called.

Edit: Or are the sleeps acting as the "blocks" until the preceding item has completed playing (ie. the first playlist Sect2_vid1.m3u has a duration of 437 seconds?) If so it shouldn't really matter, although you could simplify/streamline the workflow further:

Code:
def checkabort():

  if os.path.exists("/tmp/stop.file"):

    os.remove("/tmp/stop.file")

    sys.exit(0)

def checksleep(timeout):

  while timeout >= 0:

    checkabort()

    timeout = timeout - 1

    time.sleep(1.0)

def execute(play=None, slide=None, timeout=None):

  if play:

    xbmc.executebuiltin("PlayMedia(%s)" % play)

  if slide:

    xbmc.executebuiltin("SlideShow(%s)" % slide)

  if timeout:

    checksleep(timeout)

execute(play="/home/pi/.xbmc/userdata/playlists/video/Sect2_vid1.m3u", timeout=437)

execute(play="/home/pi/.xbmc/userdata/playlists/music/Sect2_mus1.m3u", slide="/media/TRANS_SD_B/Interlude,recursive,random", timeout=353)

Thanks Milhouse, I'll get to work on the hack.

The suggested coding has now been incorporated and works fine, I have tested it over many days. Thanks Milhouse.

2santo2

Milhouse

2santo2

2santo2