2007-06-02, 05:36
What is the window name/id for dialogbusy.xml? I am trying to make a button to activate the window so I can test it but I cant find it anywhere.
dialog = xbmc.window(138)
dialog.show()
Basje Wrote:Just out of curiousity: how would the code look to show this Busy Dialog? Something like:?Code:dialog = xbmc.window(138)
dialog.show()
jmarshall Wrote:138
Gamester17 Wrote:does http://www.xboxmediacenter.com/wiki/inde...Window_IDs need updating?